año de la consolidación del mar de grau informe

7/26/2019 Ao de La Consolidacin Del Mar de Grau Informe

1/25

AO DE LA CONSOLIDACIN DEL MAR DEGRAU

FACULTAD DE INGENIERA

ESCUELA ACADMICO PROFESIONAL DE INGENIERA CIVIL

TEMA:

EJERCICIOS DE RPIDAS Y CADAS

INTEGRANTES:

CUZCA IZAGUIRRE, Cyntia

FRANCISCO TAPIA, Daryn

MANTILLA ALFARO, Massi!

SANGAMA TORRES, Nati"i#a#

DOCENTE:

ING$ MAZA ESPONIZA OSCAR

ASIGNATURA:

O%RAS &IDRULICAS

NUEVO CHIMBOTE 2016


2/25

ESCUELA DE INGENIERA CIVIL

NDICE

I. INTRODUCCIN$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$'II. OBJETIVOS$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$(

2.1. OBJETIVO RINCIAL$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$(

2.2. OBJETIVOS SEGUNDARIOS$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$(

III. MARCO TERICO$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$)

!.1. R"IDAS$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$)

($*$*$ DATOS DE CAMPO NECESARIO PARA EL DISE+O &IDRULICO$$$$$)

($*$'$ PARTES DE UNA RPIDA$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$)

($*$($ ALCANCES DEL PROCEDIMIENTO DE DISE+O$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

!.2. CADAS$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$-

($'$*$ ELEMENTOS DE UNA CADA .ERTICAL$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$-

($'$'$ TIPOS DE CADAS .ERTICALES$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$/

($'$($ CRITERIOS DE DISE+O DE UNA CADA$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$0

IV. EJERCICIOS$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$**

V. CONCLUSIONES$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$'1

I. INTRODUCCIN

En 2n 3r4y5t4 # ri64, !a 3art 54rrs34n#int a s2 54n535i7n, #8ni#4

34r s2 3!anta9int4 :i#r;2!i54, tin 3rin5i3a! i934rtan5ia, # #4n# s #tr9inan !as strat6ias # ?2n5i4na9int4 #! sist9a

# ri64 , 34r !4 tant4, 3ara #sarr4!!ar ! 3!anta9int4 :i#r;2!i54 #!

3r4y5t4 s tin =2 i93!9ntar !4s #is@4s # !a in?rastr25t2ra

i#nti85a#a n !a ta3a # 5a934 5ana!s, 4


3/25


Un4 # !4s as35t4s =2 6nra!9nt 9r5 s35ia! atn5i7n n !

#is@4 # 4a

5inti5a =2 a#=2ir 2n 5:4rr4 !>=2i#4 34r ! in5r9nt4 # !a "!45i#a# #

24$ Esta sit2a5i7n s 3rsnta n "rt#r4s # H5#n5ias, str25t2ras

# 5a>#a, #s?462s # ?4n#4, sa!i#as # a!5antari!!as, t5$

En st tra#a, a !a " "r94s #4s

r5i5i4s #4n# n4s 92stra ! #is@4 # !!as$

II. OBJETIVOS

II.1. OBJETIVO RINCIAL

C4n45r ! 3r45s4 # #is@4 # 2na r;3i#a y 2na 5a>#a, #ntr4 #

2na 4#a$ I#nti85ar y s!55i4nar !4s ti34s # r;3i#as =2 s 32#n 2ti!iar n

2na 4


4/25

IMAGEN *K SE MUESTRA UNA RPIDA$


sri # 5a>#as s5a!4na#as st; s23#ita#4 a 2n st2#i4 54n79i54

5493arati"4$

III$*$*$ DATOS DE CAMPO NECESARIO PARA EL DISE+O &IDRULICO

S r=2ir 54n45r !as 3r43i#a#s :i#r;2!i5as y !"a5i4ns #

!a rasant y # !as s55i4ns #! 5ana! a62as arri


5/25


#4n# sa r=2ri#4, 3r9itir !a "a52a5i7n # !as a62as #!

5ana! 52an#4 !a 43ra5i7n # !a r;3i#a sa s2s3n#i#a$

'$ SECCIN DE CONTROL

Es !a s55i7n #4n# !a 54n#255i7n a29nta !as 54n#i5i4ns #! 24 s4n !as # r6i9n

5r>ti54$ M#iant !a s55i7n # 54ntr4!, s intnta #is9in2ir !as

a!tas "!45i#a#s n !a ntra#a a !as r;3i#as 3r4#25i#as 34r !

ani94 34si

# !a 3n#int$ E! r6i9n # 24 n !a r;3i#a s s23r5r>ti54 y

!a s23r85i #! a62a si62 2na 52r"a =2 s a5r5a

asint7ti5a9nt a! tirant n4r9a!$

)$ POZA DISIPADORA

O sa!i#as 54n 4a n st ti34 # str25t2ras$

S 2


6/25

IMAGEN 'K PARTES DE UNA RPIDA$


1$ UNA TRANSICIN DE SALIDA

Ca9a n ! ini5i4 # !a s55i7n #

!a r;3i#a$ Ca!52!ar !as "aria

r;3i#a$ Dtr9inar !a 6ra#int # nr6>a n ! 5ana! a62as #a #s32s

#! sa!t4 :i#r;2!i54$

Dtr9inar !a !4n6it2# # !a 34a$


7/25

IMAGEN (K SE MUESTRA UNA CADA$


.ri85ar !a 34sin62, s4n str25t2ras 2ti!ia#as n

a=2!!4s 32nt4s #4n# s n5sari4 sa!"ar #sni"!s #a s 54n#25ir a62a #s# 2na !"a5i7n a!ta

:asta 2na !"a5i7n a 6nra#a 34r sta

#i?rn5ia # ni"!s$ La #i?rn5ia # ni"! n ?4r9a # 2na 5a>#a, s

intr4#25 52an#4 sa n5sari4 # r#25ir !a 3n#int # 2n 5ana!$

La 5a>#a "rti5a! s 32# 2ti!iar 3ara 9#ir ! 5a2#a! =2 "irt s4


8/25

IMAGEN )K PARTES DE UNA CADA .ERTICAL$


*$ Transicin de entrada:Un 34r 9#i4 # 2n str5:a9int4

3r46rsi"4 !a s55i7n #! 5ana! s23ri4r 54n !a s55i7n #

54ntr4!$'$ Seccin de control: Es !a s55i7n 54rrs34n#int a! 32nt4

#4n# s ini5ia !a 5a>#a, 5r5an4 a st 32nt4 s 3rsntan !as54n#i5i4ns 5r>ti5as$

($ Cada en s: La 52a! s # s55i7n r5tan62!ar y 32# sr

"rti5a! 4 in5!ina#a$)$ P4a 4 54!5:7n a94rti62a#4rK Es # s55i7n r5tan62!ar, sin#4

s2 F2n5i7n !a # a#a$1$ Transicin de salida: Un !a 34a # #isi3a5i7n 54n ! 5ana!

a62as aas # 5492ni5a5i7n B5arrtras, ">as ?rras 2 4tr4 5ana!$

III$'$'$ TIPOS DE CADAS .ERTICALES

*$ CADAS .ERTICALES CON O%STCULOS PARA EL C&OUE

E! %2ra2 4? R5!a9ati4n, :a #sarr4!!a#4 3ara sa!t4s

3=2@4s, 2n ti34 # 5a>#a 54n 4


9/25

IMAGEN 1K CADA .ERTICAL CON O%STCULO$

IMAGEN K CADA .ERTICAL SIN O%STCULO$


# nr6>a 3ara 2na a93!ia "aria5i7n # !a 3r4?2n#i#a# # !a

!;9ina a62as a#as$ L4n6it2# transi5i7n # ntra#a$ An5:4 #! 5ana! n ! tra94 # !a 5a>#a$ Dis@ar !a 34a #isi3a#4ra n ?2n5i7n # !a a!t2ra # 5a>#a$ %4r# !i#a$

R264si#a# n ! ?2n5i4na9int4 # !a 5a>#a$ .nti!a5i7n


10/25


IV. EJERCICIOS1. DISEO DE UNA R"IDAEs 2n 3r4y5t4 # ri64, s tin 2n 5ana! !atra! =2 54n#25 2n 5a2#a! #

0.35m3/s , traa#4 n tirra (n=0,025) # s55i7n tra34i#a! 54n 2n

ta!2# Z=1 , an5:4 # s4!ra b=0,75m , y traa#4 54n 2na 3n#int #

0,5 . $


11/25


T

$0.%& '

(

*

)

En 2n tra94 # s2 3r8! !4n6it2#ina! tin =2 atra"sar 2n 3r8! 5494 s

92stra n !a 862ra$

Dis@ar 2na r;3i#a # s55i7n r5tan62!ar$

SOLUCIN:

1. DISEO DEL CANAL AGUAS ARRIBA ) AGUAS DEBAJO DE LAR"IDA:

DATOS:

Z *$

< $-1 9$

n $'1

S $1

$(1 9(s

A= (b+Zy )y

P=b+2y 1+z2

y=?

De la ecuacin de Manning

Q=1

n A R

2 /3 S

1 /2

Q=1

n

A5/3

P2 /3 S

1 /2

Hallando y

Q n

S1 /2

=3A

5

P2

R=A

P

T=b+2z


12/25


B*

B'

B(

( Q nS1 /2 )3

=A

5

P2

Despejando A y P:

A= (b+Zy ) y

A= (0.75+y )y+y

A=0.75y+y2

P=b+2y 1+z2

P=0.75+2y 2

P=0.75+2.83y

Reepla!ando en "#$:

( 0.350.0250.0051 /2 )= (0.75y+y2 )5

(0.75+2.83y )2

0.002= (0.75y+y2 )5

(0.75

+2.83y

)

2

Ta%ulando:

y f(y)

&'(& &'&

&')*&'&&&+

,

0.35 0.002&'*& &'&)&

0.002=(0.75(0.35)+(0.35)2 )5

(0.75+2.83(0.35))2

0.002=0.002

y=0.35

Repla!ando y en ")$ y "($

A=0.75y+y2

A=(0.35)y+(0.35)2

A=0.39 m2

P=0.75+2.83y

P=0.75+2.83(0.35)

P=1.74 m

Hallando radio -idr.ulico yespejo:

R=A

P

R=0.39

1.74

R=0.22m


13/25


T=b+2zy

T=0.75+2 (0.35)

T=1.45m

Hallando /elocidad0 energacin1tica y energa especi2ca:

V=Q

A

V=0.35

0.39

V=0.90

hv=v

2

2 g

hv= (0.90 )2

29.81

hv=0.041m

E=y+hv

E=0.35+0.041

E=0.391m

2. CALCULO DEL ANCHO DE

SOLERA EN LA R"IDA ) EL

TIRANTE EN LA SECCIN DE

CONTROL:

Anc-o de la solera en lar.pida:

Seg3n Daren4o/:

b=0.765Q2/5

b=0.765(0.35)2/5

b=0.50m

Tirante en la seccin de

control:

YC=3

Q

2

b2

g

YC=3

(3.35)2

(0.50)2 9.81

YC=0.22m0.25m

!. DISEO DE LA TRANSICIN

DE ENTRADA:

L= T

1T

2

2tan (22.5 )

L= 1.450.502tan(22.5 )

L=1.15m


14/25


*.

CALCULO HIDR"ULICO EN EL

CANAL DE LA R"IDA

+'#' CA5C657 D8

T9RAT8S ; D9STAC9AS:

y A RV=

Q

AV

2

2 g E=y+

V2

2g

&')

*

&'#

)*

&'#

)*

)'< &'#

+&'(=

&'))

&'##

&'##>

('#< &'*#*

&'>(*

&')

&

&'#

&

&'#

#('*&

&',

)+&'


15/25


EGE=(15.40.05 )+0.25+0.14

EGE=1.16

Cuando y &'))

EGE=(15.40.05 )+0.22+0.515

EGE=1.505

Cuando y &')&

EGE=(15.4

0.05

)+0.20

+0.624

EGE=1.594

*')' CA5C657 D8 5A C6R@A 858@AC9 T9RAT8 C7E6FAD7

M87R:

y1

=0.20 b=0.50 Q=0.35

y2=y

1

2+2

Q2

g y1

+y

1

2

4

y2=0.20

2

+

2(0.35)2

b(9.81)0.20

+0.20

2

4

y2=0.41m

6. CALCULO DE LA RO+UNDIDAD DEL COLCHN AMORTIGUADOR

h=!!va"#$n"ana!!va"#$n"$"h$n


16/25


E!va"# % n d! "ana :(h)

%. CALCULO DE LA LONGITUD DEL COLCHN

L=&(y2y1)

L=5(0.410.20)

L=01.05m

T/' L = 1. 00m

. TRANSICIN DE SALIDA IGUAL A TRANSICIN DE ENTRADA.

L=1.15m

h=y+10'L

h=0.35+0.10

h=hy2

h=0.450.41


17/25


EJEMLO N3 02: DISEO DE UNA CADA.

En ! 3r4y5t4 # ri64 s tin =2 54nstr2ir 2n 5ana! !atra! =2 54n#25a

0.5m3/s .

D a52r#4 a !as 54n#i5i4ns t4346r;85as ! 3r8! !4n6it2#ina! #! 5ana!

tin 2na t4346ra?>a 5494 s 92stra n !a i9a6n a#2nta$

A3r4"5:an#4 # s2s 54n45i9int4s n str25t2ras :i#r;2!i5as s ! 3i#54!a


18/25


($ Dis@ar 2na 5a>#a "rti5a! =2 sir"a 3ara sa!"ar !as #i?rn5ias #

!"a5i7n$

SOLUCIN

1. DISEO DEL CANAL DE TIERRA.

*$*$ DISE+O DE CANAL AGUAS ARRI%A

Suponiendo el diseGo del canal aguas arri%a0 consideraos ue es de

.Iia e2ciencia -idr.ulica y nia in2ltracin:

R=Y

2

b

y=3 tan( (2 )

y

<

DATOS:

n=0.025

S=0.001

Q=0.5m3/s


19/25


B*

b

y=3 tan( 902)

b=3 y

D !a 52a5i7n # Mannin6K

Q=1

n A R

2 /3 S

1 /2

Q n

S1 /2 =A R2 /3

C4nsi#ra94s 2na r264si#a# # $'1 34r sr 2n 5ana! n tirraK

0.50.025

(0.001 )1/2=A R2 /3

Ca!52!an#4 ;ra #! 5ana! tra34i#a! a62as arri


20/25


0.395=3y2 (Y2)2/3

0.395=3y2 y

2 /3

1,5874

0.3951,5874=3y 2 y2/3

0.627=3y8/3

0.209=3

y8

(0.209)3=y8

8

0.2093=y

0.56m=y

NOTA:! 5ana! a62as arri


21/25


Resol/iendo las ecuaciones:

%ASEK

b=3 y

b=3(0.56)

b=1.68m

REAK

A=by

A=1.68) 0.56

A=0.94m2

PERMETROK

P=2 y+b

P=2 (0.56 )+1.68 P=2.8m

ESPEJOK

T=b

T=1.68m

RADIO &IDRULICOK

R=A

P

R=0.34m

DISEO DE CADAS VERTICALES

Calculo del anc-o de la cada y el tirante en la seccin de control'

ANC&O DE LA CADAK


22/25


b=0.765) Q2

5

b=0.765)0.502

5

b=0.58m

E93>ri5aK

b=18.78Q

10.11+Q

b=1.25m

TIRANTE CRITICOK

Y"=3 Q

2

b2

g

Y"=3 0.50

2

1.2529.81

Y"=0.25m

DiseGo de transicin de entrada:

L=T1T22*g 22.5

L=1.681.252 *g 22.5

L=0.52m

Calculo de transicin de salida "igual a la transicin de entrada$'

L=0.52m

Diensiones de la cada:

: #sni"!

* Q 00$' $/ 9


23/25


CADAS .ERTICALES SIN O%STCULOS

uero de cadas

+=(Y"h

3

)

+=0.031

Par.etros de la cada /ertical

Ld=4.30h +0.27

Ld=4.30 (0.8)0.0310.27

Ld=1.35m

y1=0.59 h +0.27

y1=0.59(0.8)0.0310.27

y1=0.11m

y2=1.66h +0.27

y2=1.66(0.8)0.0310.27

y2=0.52m


24/25


y,=h +0.22

y,=(0.8)0.0310.22

y,=0.37m

5ongitud del resalto

L=5(Y2Y1)

L=5(0.520.11)

L=2.05m

5ongitud total del colc-n

=Ld+L

=1.35+2.05

=3.40m

V. CONCLUSIONES

Para !

str25t2ras s4YP ES LA ALTURA UE APUNTA EL IMPULSE &ORIZONTALNECESARIO PARA UE EL C&ORRO DE AGUA MARC&E &ACIA


25/25


EHistn #i"rs4s ti34s # str25t2ras 3ara ! #is@4 # r;3i#as !a 52a!

s !6ir; #3n#in#4 # !a t4346ra?>a #! trrn4 4 ! #sni"! =2

Hista n ! 5ana!$

C4n !a ay2#a # !4s #4s r5i5i4s :94s 34#i#4 5493rn#r a!64

94r !4s t9as # 5a>#as y r;3i#as$

año de la consolidación del mar de grau informe

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